Integrand size = 27, antiderivative size = 189 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=-3 a b x+\frac {\left (3 a^2-2 b^2\right ) \text {arctanh}(\cos (c+d x))}{2 d}-\frac {\left (4 a^2-23 b^2\right ) \cos (c+d x)}{6 d}-\frac {b \left (a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{3 a d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d} \]
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Time = 0.33 (sec) , antiderivative size = 189, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2972, 3128, 3112, 3102, 2814, 3855} \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {\left (3 a^2-2 b^2\right ) \text {arctanh}(\cos (c+d x))}{2 d}-\frac {\left (4 a^2-23 b^2\right ) \cos (c+d x)}{6 d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \left (a^2-3 b^2\right ) \sin (c+d x) \cos (c+d x)}{3 a d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-3 a b x \]
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Rule 2814
Rule 2972
Rule 3102
Rule 3112
Rule 3128
Rule 3855
Rubi steps \begin{align*} \text {integral}& = -\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-\frac {\int \csc (c+d x) (a+b \sin (c+d x))^2 \left (3 a^2-2 b^2+2 a b \sin (c+d x)-\left (2 a^2-3 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{2 a^2} \\ & = -\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-\frac {\int \csc (c+d x) (a+b \sin (c+d x)) \left (3 a \left (3 a^2-2 b^2\right )+11 a^2 b \sin (c+d x)-4 a \left (a^2-3 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{6 a^2} \\ & = -\frac {b \left (a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{3 a d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-\frac {\int \csc (c+d x) \left (6 a^2 \left (3 a^2-2 b^2\right )+36 a^3 b \sin (c+d x)-2 a^2 \left (4 a^2-23 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{12 a^2} \\ & = -\frac {\left (4 a^2-23 b^2\right ) \cos (c+d x)}{6 d}-\frac {b \left (a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{3 a d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-\frac {\int \csc (c+d x) \left (6 a^2 \left (3 a^2-2 b^2\right )+36 a^3 b \sin (c+d x)\right ) \, dx}{12 a^2} \\ & = -3 a b x-\frac {\left (4 a^2-23 b^2\right ) \cos (c+d x)}{6 d}-\frac {b \left (a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{3 a d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d}-\frac {1}{2} \left (3 a^2-2 b^2\right ) \int \csc (c+d x) \, dx \\ & = -3 a b x+\frac {\left (3 a^2-2 b^2\right ) \text {arctanh}(\cos (c+d x))}{2 d}-\frac {\left (4 a^2-23 b^2\right ) \cos (c+d x)}{6 d}-\frac {b \left (a^2-3 b^2\right ) \cos (c+d x) \sin (c+d x)}{3 a d}-\frac {\left (2 a^2-3 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{6 a^2 d}-\frac {b \cot (c+d x) (a+b \sin (c+d x))^3}{2 a^2 d}-\frac {\cot (c+d x) \csc (c+d x) (a+b \sin (c+d x))^3}{2 a d} \\ \end{align*}
Time = 2.15 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.01 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {-6 \left (4 a^2-5 b^2\right ) \cos (c+d x)+2 b^2 \cos (3 (c+d x))+3 \left (-24 a b c-24 a b d x-8 a b \cot \left (\frac {1}{2} (c+d x)\right )-a^2 \csc ^2\left (\frac {1}{2} (c+d x)\right )+12 a^2 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-8 b^2 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-12 a^2 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+8 b^2 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+a^2 \sec ^2\left (\frac {1}{2} (c+d x)\right )-4 a b \sin (2 (c+d x))+8 a b \tan \left (\frac {1}{2} (c+d x)\right )\right )}{24 d} \]
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Time = 0.54 (sec) , antiderivative size = 157, normalized size of antiderivative = 0.83
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\frac {\cos ^{5}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{3}\left (d x +c \right )\right )}{2}-\frac {3 \cos \left (d x +c \right )}{2}-\frac {3 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{2}\right )+2 a b \left (-\frac {\cos ^{5}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )+b^{2} \left (\frac {\left (\cos ^{3}\left (d x +c \right )\right )}{3}+\cos \left (d x +c \right )+\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )\right )}{d}\) | \(157\) |
default | \(\frac {a^{2} \left (-\frac {\cos ^{5}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{3}\left (d x +c \right )\right )}{2}-\frac {3 \cos \left (d x +c \right )}{2}-\frac {3 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{2}\right )+2 a b \left (-\frac {\cos ^{5}\left (d x +c \right )}{\sin \left (d x +c \right )}-\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )+b^{2} \left (\frac {\left (\cos ^{3}\left (d x +c \right )\right )}{3}+\cos \left (d x +c \right )+\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )\right )}{d}\) | \(157\) |
parallelrisch | \(\frac {\left (-288 a^{2}+192 b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )-36 \left (\cos \left (d x +c \right )-\frac {11 \cos \left (2 d x +2 c \right )}{12}-\frac {\cos \left (3 d x +3 c \right )}{3}+\frac {11}{12}\right ) \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2} \left (\csc ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-216 b \left (\cos \left (d x +c \right )-\frac {\cos \left (3 d x +3 c \right )}{9}\right ) \sec \left (\frac {d x}{2}+\frac {c}{2}\right ) a \csc \left (\frac {d x}{2}+\frac {c}{2}\right )-576 a b x d +240 \cos \left (d x +c \right ) b^{2}+16 \cos \left (3 d x +3 c \right ) b^{2}+256 b^{2}}{192 d}\) | \(162\) |
risch | \(-3 a b x +\frac {b^{2} {\mathrm e}^{3 i \left (d x +c \right )}}{24 d}+\frac {i a b \,{\mathrm e}^{2 i \left (d x +c \right )}}{4 d}-\frac {a^{2} {\mathrm e}^{i \left (d x +c \right )}}{2 d}+\frac {5 b^{2} {\mathrm e}^{i \left (d x +c \right )}}{8 d}-\frac {a^{2} {\mathrm e}^{-i \left (d x +c \right )}}{2 d}+\frac {5 \,{\mathrm e}^{-i \left (d x +c \right )} b^{2}}{8 d}-\frac {i a b \,{\mathrm e}^{-2 i \left (d x +c \right )}}{4 d}+\frac {b^{2} {\mathrm e}^{-3 i \left (d x +c \right )}}{24 d}-\frac {i a \left (i a \,{\mathrm e}^{3 i \left (d x +c \right )}+i a \,{\mathrm e}^{i \left (d x +c \right )}+4 b \,{\mathrm e}^{2 i \left (d x +c \right )}-4 b \right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{2}}+\frac {3 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{2 d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right ) b^{2}}{d}-\frac {3 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{2 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right ) b^{2}}{d}\) | \(284\) |
norman | \(\frac {\frac {a b \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {a^{2}}{8 d}+\frac {a^{2} \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {\left (23 a^{2}-32 b^{2}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {\left (33 a^{2}-32 b^{2}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{12 d}-\frac {\left (43 a^{2}-32 b^{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d}-\frac {a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}-\frac {4 a b \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {4 a b \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-3 a b x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-9 a b x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-9 a b x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-3 a b x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}-\frac {\left (3 a^{2}-2 b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d}\) | \(297\) |
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Time = 0.29 (sec) , antiderivative size = 210, normalized size of antiderivative = 1.11 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {4 \, b^{2} \cos \left (d x + c\right )^{5} - 36 \, a b d x \cos \left (d x + c\right )^{2} + 36 \, a b d x - 4 \, {\left (3 \, a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right )^{3} + 6 \, {\left (3 \, a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right ) + 3 \, {\left ({\left (3 \, a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - 3 \, a^{2} + 2 \, b^{2}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 3 \, {\left ({\left (3 \, a^{2} - 2 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - 3 \, a^{2} + 2 \, b^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 12 \, {\left (a b \cos \left (d x + c\right )^{3} - 3 \, a b \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, {\left (d \cos \left (d x + c\right )^{2} - d\right )}} \]
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Timed out. \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\text {Timed out} \]
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Time = 0.28 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.79 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=-\frac {12 \, {\left (3 \, d x + 3 \, c + \frac {3 \, \tan \left (d x + c\right )^{2} + 2}{\tan \left (d x + c\right )^{3} + \tan \left (d x + c\right )}\right )} a b - 2 \, {\left (2 \, \cos \left (d x + c\right )^{3} + 6 \, \cos \left (d x + c\right ) - 3 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )} b^{2} - 3 \, a^{2} {\left (\frac {2 \, \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{2} - 1} - 4 \, \cos \left (d x + c\right ) + 3 \, \log \left (\cos \left (d x + c\right ) + 1\right ) - 3 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{12 \, d} \]
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Time = 0.37 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.33 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {3 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 72 \, {\left (d x + c\right )} a b + 24 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 12 \, {\left (3 \, a^{2} - 2 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) + \frac {3 \, {\left (18 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 12 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 8 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a^{2}\right )}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}} + \frac {16 \, {\left (3 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 6 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 6 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 6 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 3 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3 \, a^{2} + 4 \, b^{2}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3}}}{24 \, d} \]
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Time = 11.23 (sec) , antiderivative size = 397, normalized size of antiderivative = 2.10 \[ \int \cos (c+d x) \cot ^3(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{8\,d}-\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (\frac {3\,a^2}{2}-b^2\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (\frac {17\,a^2}{2}-16\,b^2\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {35\,a^2}{2}-16\,b^2\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {19\,a^2}{2}-\frac {32\,b^2}{3}\right )+\frac {a^2}{2}+20\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+12\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5-4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+4\,a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left (4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+12\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+12\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\right )}+\frac {6\,a\,b\,\mathrm {atan}\left (\frac {36\,a^2\,b^2}{-18\,a^3\,b+36\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,a^2\,b^2+12\,a\,b^3}-\frac {12\,a\,b^3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{-18\,a^3\,b+36\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,a^2\,b^2+12\,a\,b^3}+\frac {18\,a^3\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{-18\,a^3\,b+36\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,a^2\,b^2+12\,a\,b^3}\right )}{d}+\frac {a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d} \]
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